Infinite nested roots. Answer 2016 or maybe not? Try it.

Algebra Level 3

There is a function

f ( x ) = x + x + x + x + . . . . f\left( x \right) =\sqrt { x+\sqrt { x+\sqrt { x+\sqrt { x+.... } } } }

and there are two numbers, a a and b b , both integers. It is known that:

1. f ( a ) × f ( b ) = 999 f(a) \times\ f(b) = 999

2. f ( a ) + f ( b ) = 64 f(a) + f(b) = 64

But, unfortunately a + b is uknown. Let change that!


The answer is 2034.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Kay Xspre
Jan 7, 2016

We can write f ( x ) f(x) as ( f ( x ) ) 2 f ( x ) = x (f(x))^2-f(x) = x . From f ( a ) f(a) and f ( b ) f(b) , we can conclude that f ( a ) = 37 f(a) = 37 and f ( b ) = 27 f(b) = 27 (swapping a a and b b would be unchanged). a a is then equal to 3 7 2 37 = 1332 37^2-37 = 1332 and b b equals to 2 7 2 27 = 702 27^2-27 = 702 , thus, a + b = 2034 a+b = 2034

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...