Given that , and an odd positive integer , let:
If the following conditions are true:
What is the least possible value of if it must be a perfect square ?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
First, it is best to express n → ∞ lim a n in a simpler way. Let S denote this expression.
S = n → ∞ lim a n
The limit can be expressed as an infinitely nested logarithmic expression:
S = b lo g ( a 1 + b lo g ( a 1 + b lo g ( a 1 + . . . ) . . . ) )
...which can be expressed as:
S = b lo g ( a 1 + S )
Since b is an odd positive integer, the equation can be rearranged as:
a 1 + S = 1 0 b S
By arduous trial and error, we come up with some possible "practical" solutions:
a 1 = 1 , b = 9 , S = 9 a 1 = 4 , b = 2 4 9 9 , S = 9 9 9 6 a 1 = 9 , b = 1 , S = 1
Since a 1 > 1 , the least possible perfect square value for a 1 is 4 .