n → ∞ , n multiple of 4 7 lim n sin ( 4 n π ) sin ( 4 n 2 π ) … sin ( 4 n ( 4 7 n − 1 ) π ) = ?
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@Satyajit Mohanty @Pi Han Goh could u guyz help me out with the integral
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let
L = n → ∞ lim n sin ( 4 n π ) sin ( 4 n 2 π ) . . . . . . . . . sin ⎝ ⎛ 4 n ( 4 7 n − 1 ) π ⎠ ⎞
ln ( L ) = n → ∞ lim n 1 r = 1 ∑ 4 7 n − 1 ln ( sin ( 4 n r π ) )
Reimann integration method
ln L = ∫ 0 4 7 1 ln ( sin ( 4 π x ) ) d x
Frankly i used wolfram alpha after this step
ln L = − 0 . 1 0 8
L = e − 0 . 1 0 8 = 0 . 8 9 7