the value of 5 + 2 1 5 + 2 3 + 8 3 + 1 2 8 3 + 1 2 8 2 × 2 3 . . . ∞ can be expressed as n . find n this is part of the set the Radicals
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I practically solved it by estimation... 8 is small enough to estimate ( and the answer most probably wouldnt be 9)
Nice problem! I liked how the quadratic solved nicely.
Aareyan, I am sorry that you had to deal with a message from a troll. I have since deleted the conversation thread, and also deactivated the account.
That behavior is not tolerated on Brilliant.
How can I figure out how a particular statement can also be written as? I solved the problem using estimation but I would also like to know the method in which problems like these are solved.
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2 3 + 8 3 + 1 2 8 3 + 1 2 8 2 × 2 3 . . . ∞ can be written as 2 3 + 2 1 2 3 + 2 1 2 3 + 2 1 . . . ∞ which is 2 3 + 2 1 x = x solve x = 1 . 5 now insert tis value and solve