Take the compound
N a X 2 ( S i X 1 2 O X 4 ) ( O H ) X 6 P b X x
The solutions for x be x 1 , x 2 ,... x n where n ∈ N .
S = ⌊ i = 1 ∑ n x i ⌋ + ⌊ i = 1 ∏ n x i ⌋ .
Now take the value of S ,
Which of the following is/are correct?
For the formation of Borazine, We need the ratio of B X 2 H X 6 : x N H X 3 , then x = S .
For the formation of Borazine, We need the ratio of B X 2 H X 6 : x N H X 3 , then x = ⌊ 2 S + 1 ⌋ .
For the formation of Borazine, We need the ratio of B X 2 H X 6 : x N H X 3 , then x = ⌊ 2 S ⌋ .
The total number of B − O − B bonds present in N a X 2 B X 4 O X 7 = S
The half of the number of water of crystallisation in N a X 2 B X 4 O X 7 ⋅ 1 0 H X 2 O = S.
One more than the total number of Oxygen bonded with Silicon in S i O X 2 = S
Enter the answer as a product of the option numbers.
Clarification
This question made by me is Purely Original from the chapter p block elements
Try my set Block Chemistry
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@Aaron Jerry Ninan , How was that?
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@Md Zuhair It was great!!!
can u please tell how to calculate charge on Si12O4
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@Aaron Jerry Ninan , @Thomas Jacob , @Rahil Sehgal . Try this qs plz