Inorganic is'nt always Memorizing -2

Chemistry Level 5

Take the compound

N a X 2 ( S i X 12 O X 4 ) ( O H ) X 6 P b X x \ce{Na2(Si_{12}O4)(OH)6 Pb_{x}}

The solutions for x x be x 1 x_{1} , x 2 x_{2} ,... x n x_{n} where n N n \in \mathbb{N} .

S = i = 1 n x i + i = 1 n x i S= \lfloor \sum^{n}_{i=1} x_{i} \rfloor + \lfloor \prod^{n}_{i=1} x_{i} \rfloor .

Now take the value of S S ,

Which of the following is/are correct?

  1. For the formation of Borazine, We need the ratio of B X 2 H X 6 : x N H X 3 \ce{B2H6}:x\ce{NH3} , then x = S x=S .

  2. For the formation of Borazine, We need the ratio of B X 2 H X 6 : x N H X 3 \ce{B2H6}:x\ce{NH3} , then x = S + 1 2 x= \lfloor \dfrac{S+1}{2} \rfloor .

  3. For the formation of Borazine, We need the ratio of B X 2 H X 6 : x N H X 3 \ce{B2H6}:x\ce{NH3} , then x = S 2 x= \lfloor \dfrac{S}{2} \rfloor .

  4. The total number of B O B \ce{B-O-B} bonds present in N a X 2 B X 4 O X 7 = S \ce{Na2B4O7} = S

  5. The half of the number of water of crystallisation in N a X 2 B X 4 O X 7 10 H X 2 O \ce{Na2B4O7.10H2O} = S.

  6. One more than the total number of Oxygen bonded with Silicon in S i O X 2 = S \ce{SiO2}=S

Enter the answer as a product of the option numbers.

Clarification

  • If answers are 1,2,3 then enter the value 1 × 2 × 3 = 6 1 \times 2 \times 3 = \boxed{6}

This question made by me is Purely Original from the chapter p block elements



Try my set Block Chemistry


The answer is 72.

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1 solution

Md Zuhair
Feb 27, 2018

@Aaron Jerry Ninan , How was that?

Md Zuhair - 3 years, 3 months ago

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@Md Zuhair It was great!!!

Aaron Jerry Ninan - 3 years, 3 months ago

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Thanks Bro!! :D

Md Zuhair - 3 years, 3 months ago

It wasn't quite memorizing, right?

Md Zuhair - 3 years, 3 months ago

Hey Aaron, Can you help me in a thing. I forgot how i arranged to find out the values of x in this question. Can you help?

Md Zuhair - 3 years ago

can u please tell how to calculate charge on Si12O4

Adarsh Agrawal - 3 years, 3 months ago

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