Say we have the following compound
( S i X 7 O X 1 7 ) ( O H ) X 4 K X 2 F e X I I X x F e X I I I X y
Now take the value of x × y .
Which of these is/are equal to x × y
The number of double bonds present in A l X 4 C X 3
The square root of the number of 2 c − 2 e bonds present in B X 2 H X 6
The number of B − O − B present in N a X 2 B X 4 O X 7
The square root of the number of B − O H present in N a X 2 B X 4 O X 7 complex.
The cube root of the number of water of crystallistation present in N a X 2 B X 4 O X 7 ⋅ 1 0 H X 2 O .
The number of triple bonds present in A l X 4 C X 3
Enter the answer as a product of the option numbers.
Clarification
If answers are 1,2,3 then enter the value 1 × 2 × 3 = 6
Here F e X I I and F e X I I I are Ferrous(II) ion and Ferric(III) ion.
This question made by me is Purely Original from the chapter p block elements
Try my set Block Chemistry
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Hit and trail worked there, if I assume another point on that line for which x ∗ y gives another value then how will you solve it?
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i didnt got your query. can you please say it clearly?
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If I took x = 4 and y = 0 then the answer would be none of these.
Isnt Al4C3 an ionic compound? how can it have double/triple bonds?
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No no. Its an covalent compound. You can see the structure in net!
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Relevant wiki: Inorganic chemistry
Lets try this!
Okay...
So We know that the general formula for cyclic/ring silicates is ( S i X n O X 3 n ) X − 2 n
Now lets make the term a bit more confined...
( S i X 7 O X 1 7 ) ( O H ) X 4 K X 2 F e X I I X x F e X I I I X y ⟹ ( S i X 7 O X 2 1 ) H X 4 K X 2 F e X I I X x F e X I I I X y
So for cyclic silicates with n=7 we get the charge for S i X 7 O X 2 1 which is nothing but − 1 4 .
Now we have oxidation for number of H and K to be + 1 .
Again for F e X I I X x and F e X I I I X y are +2 and +3 resp.
So we have the oxidation number of total compound = 0
⟹ 2 x + 3 y − 1 4 + 4 + 2 = 0
⟹ 2 x + 3 y = 8
⟹ y = 2 and x = 1 ...
So we get x × y = 2
Now the options are structure related.
So
There are 2 double bonds in A l X 4 C X 3 [ C O R R E C T ]
There are 4 2c-2e bonds in B X 2 H X 6 [ C O R R E C T ]
There are 5 B − O − B bonds present. [ W R O N G ]
There are 4 B-OH bonds present in N a X 2 B X 4 O X 7 complex. [ C O R R E C T ]
The water of crystallisation in N a X 2 B X 4 O X 7 is 8. [ C O R R E C T ]
Number of triple bonds in A l X 4 C X 3 is 2. [ C O R R E C T ]