In a right angled triangle △ A B C with ∠ C = 9 0 ∘ with r + r A + r B = r C = 3 5 .
Find the perimeter of △ A B C .
Details and Assumptions :
r is inradius.
r A , r B , r C are radii of excircles opposite to vertices A , B , C .
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semiperimeter=Rc
we simply use the fact that excenter lie on internal angle bisector of C and use a little geometry.
The first part is/was unnecessary. rc=0 was enough
Well it must be mentioned that it is right angled at C.
Anyways in a right triangle.
s ( s − c ) = Δ where s is the semi permeter.
Also r c = s − a Δ
Rest is self explanatory.
Actually , I had mentioned that earlier. But someone from the moderators has edited this question.
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