A drinking straw of length
and mass
is placed on a square table of side
parallel to one of its sides such that one third of its length extends beyond the table. An insect of mass
lands on the inner end of the straw (ie, the end which lies on the table) and walks along the straw until it reaches the outer end. It does not topple even when another insect lands on top of the first one. Find the largest mass of the second insect that can have without toppling the straw. Neglect friction.
Take
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When the insect went from one end to another the end the net force on the system ( s t r a w + i n s e c t ) is 0 . So the centre of mass of the system remains at the same position i . e it doesn't get displaced. So when insect goes further the straw moves somewhat backwards so find the final position of the straw. Now when the another insect sits on the first one the straw will not topple till the centre of mass of the system just comes at one end of the square plate so find the mass of this insect such that its centre of mass just come at its end.solving for it you will get mass of the insect to be 5 m