Insisting with the basics

Let's suppose A A and B B be events in a sample space Ω \Omega , with P ( A ) = 0.5 P(A) = 0.5 , P ( A B ) = 0.7 P(A \cup B) = 0.7 and P ( A B ) = 0.4 P(A|B) = 0.4 .

Calculate P ( B ) P(B) .


The answer is 0.3333.

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1 solution

We have that P ( A B ) = P ( A ) + P ( B ) P ( A B ) P(A \cup B) = P(A) + P(B) - P(A \cap B)

P ( A B ) = P ( A ) + P ( B ) P ( A B ) = 0.5 + P ( B ) 0.7 = P ( B ) 0.2 \Longrightarrow P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.5 + P(B) - 0.7 = P(B) - 0.2 .

Now P ( A B ) = P ( A B ) P ( B ) P ( A B ) = P ( A B ) P ( B ) P(A|B) = \dfrac{P(A \cap B)}{P(B)} \Longrightarrow P(A \cap B) = P(A|B)*P(B) , and so

P ( B ) 0.2 = 0.4 P ( B ) 0.6 P ( B ) = 0.2 P ( B ) = 0.333 P(B) - 0.2 = 0.4*P(B) \Longrightarrow 0.6*P(B) = 0.2 \Longrightarrow P(B) = \boxed{0.333} to 3 decimal places.

Exact Brian, thank you, (+1) \uparrow

Guillermo Templado - 4 years, 9 months ago

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