Inspiration

Classical Mechanics Level 4

If the moment of inertia of half ring of radius R R and M M about its centre of mass and perpendicular to the plane of the ring is of the form of γ M R 2 \gamma MR^2 . Find γ \gamma .

Inspiration .


The answer is 0.594715265.

Rishabh Deep Singh by Rishabh Deep Singh , 23, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Nilav Rudra
Feb 24, 2016

by using the parallel axis theorem I= I C M I_{CM} + M D 2 MD^{2}

D= 2 R π \frac{2R}{π}

I= M R 2 MR^{2}

so , I C M I_{CM} =I- M D 2 MD^{2} = M R 2 MR^{2} X [ 1 − 4 Π 2 ] \left[ 1-\frac { 4 }{ { \Pi }^{ 2 } } \right] which is equal to 0.594715265 M R 2 MR^{2}

2 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...