Inspired by Aditya Kumar

x + y x 2 + y 2 = 1 10 \large \dfrac{x+y}{x^2+y^2} =\dfrac1{10}

Find the number of pairs of integers ( x , y ) (x,y) that satisfy the equation above.


The answer is 11.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Tran Hieu
Mar 26, 2016

From the equation we could have ( x 5 ) 2 + ( y 5 ) 2 = 50 (x-5)^{2} + (y-5)^{2} = 50

So we could have [ ( x 5 ) 2 ; ( y 5 ) 2 ] = [ 1 ; 49 ] o r [ 49 ; 1 ] o r [ 25 ; 25 ] [(x-5)^{2};(y-5)^{2}] = [1;49] or [49;1] or [25;25]

Each of the above could generate 4 pair of (x,y) but for the last one we have (0,0) pair that need to remove. So total we have 11 \boxed{11} pairs.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...