Let be the sum of the numbers from to , inclusive. Let be equal to . What is the remainder when is divided by ?
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f ( x ) is the same as ( 2 n + 1 ) . So, what the problem is asking for is ( 2 2 ) + ( 2 3 ) + ( 2 4 ) + . . . + ( 2 2 0 1 8 ) . Using the Hockey Stick Theorem, we can see that this is equal to ( 3 2 0 1 9 ) which is equal to 1 , 3 6 9 , 6 5 7 , 9 6 9 . The last three digits are 9 6 9