Inspired by Ashik Muhammad

Geometry Level 3

Consider a box with the dimensions 20 × 14 × 7 20 \times 14 \times 7 . What is the shortest distance a small spider must walk along the inside walls to get from one corner of the box to the opposite corner?


Inspiration .


The answer is 29.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Maria Kozlowska
Nov 6, 2015

Drawing a net of the box and connecting corners gives three possible solutions: ( 20 + 7 ) 2 + 1 4 2 > 30 \sqrt{(20+7)^2 + 14^2}>30 , ( 20 + 14 ) 2 + 7 2 > 34 \sqrt{(20+14)^2 + 7^2}>34 and ( 14 + 7 ) 2 + 2 0 2 = 29 \sqrt{(14+7)^2 + 20^2} = 29

Very nice (+1)! The figure is very helpful indeed. For completeness, we should also consider the diagonal of a (20+14) x 7 rectangle... we can quickly reject this case since the diagonal is longer than 34.

Otto Bretscher - 5 years, 7 months ago

Log in to reply

You are right, I missed the third option. I updated the solution.

Maria Kozlowska - 5 years, 7 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...