Consider a square-based prism whose vertices are given as described above. It can be considered as a tilted cube, where the top face is shifted one unit right and one unit up compared to the bottom face.
Does the south (blue) face and the west (green) face have the same surface area?
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Blue face is the floor of the slanted cube, and compared to a regular one, it didn't undergo any makeover (along with the ceiling of it). Green and it's opposite wall are now not two perpendicular walls in regards to the xy-plane anymore, but two sloped inclination of 45° (or was it 135° for the other wall?) with the same perpendicular height in comparison to any regular cube with the same base floor. Thus, with the slant height factored in (slant height > perpendicular height), West wall's surface area > South floor's surface area.