Inspired by Calvin Lin!
If someone tells you
⎣ ⎢ ⎡ ⎝ ⎛ ⎝ ⎛ ( ( ( 3 5 0 ) 2 − 1 ) 9 ) 3 1 ⎠ ⎞ ⎠ ⎞ − 2 + ∑ n = 1 ∞ n ( n + 1 ) 1 + 6 n 1 s i n x ⎦ ⎥ ⎤ [ n d ( d + n ) ] − 1 × ( d + n ) + ( k w + e 2 ) + ( ( d s ) − 1 ( e 2 n ) 2 1 ) + ( ( a r ) − 1 y e − 1 1 )
what is he saying?
Inspiration, Too many celebrations going around
This problem is created by me! But two of the expressions were taken from @Satvik Golechha
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2 solutions
Actually that's easier, upvoted!
We just need to figure out the square bracket to solve.
\large \begin{aligned} \left[ \left( \left( \left( \left( \left( \left( \sqrt [ 3 ]{ 50 } \right) ^{ \frac { 1 }{ -2 } } \right) ^{ 9 } \right) ^{ \frac { 1 }{ 3 } } \right) \right) ^{ -2 }+\sum _{ n=1 }^{ \infty } \frac { 1 }{ n(n+1) } +\frac { \frac { 1 }{ n } sinx }{ 6 } \right] =\left[ 50^{ \frac { 1 }{ 3 } \times \frac { 1 }{ -2 } \times 9\times \frac { 1 }{ 3 } \times -2 }+\sum _{ n=1 }^{ \infty } \frac { 1 }{ n(n+1) } +\frac { \frac { 1 }{ n } sinx }{ 6 } \right] \\ =\left[ 50^{ 1 }+\sum _{ n=1 }^{ \infty } \frac { 1 }{ n(n+1) } +\frac { \frac { 1 }{ n } sinx }{ 6 } \right] \\ =50+\sum _{ n=1 }^{ \infty } \frac { 1 }{ n } -\frac { 1 }{ n+1 } +\frac { six }{ 6 } \right] & \\ & =50+1+1 \\ & =52 \end{aligned}
Since we know what the first number is, we have sufficient information to determine the answer.
You have L A T E X error.
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Where? I can't find it.
Yeah @Sharky Kesa . There is L a T e X Error In our solution.
I think you need to add a "\left" in the appropriate place, atleast that's what the DAUM EQUATION EDITOR is showing when I copied the same content. . .
Edited it.
Nicely done! Up voted.
I looked at the variable letters of the equation and compared to the given options.