Classify all positive integer values of such that
In the options, is a positive integer.
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The factor x^2+x+1 has the complex cube root of unity, w as one it's factors. Thus putting x=w in the polynomial, (x+1)^n-1-x^n, we get,. (-w^2)^n-1-w^n, which vanishes if n is an odd integer and not a multiple of 3. Thus integers of the form 6n+1 satisfy.