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Extending my solution to "Previous Part", whose link is given at the end of the problem, we see that x^2+x+1 divides the polynomial. But for (x^2+x+1)^2 to divide the polynomial it means that x=w is a repeated root of the above. Let P(x)=(1+x)^n-1-x^n. Differentiating, P'(x)=n((1+x)^(n-1)-x^(n-1)). Since n was of the form 6k+1, n-1 = 6k. Thus once again the polynomial is vanishes when we put x=w.