Inspired by Jason Chrysoprase

Algebra Level 5

True or false:

a) The polynomial p ( x ) = x 2 + 1 C [ x ] p(x) = x^2 + 1 \in \mathbb{C}[x] is an irreducible polynomial over C \mathbb{C}

b) The polynomial p ( x ) = x 2 + 1 Z 2 [ x ] p(x) = x^2 + 1 \in \mathbb{Z}_2 [x] is an irreducible polynomial over Z 2 \mathbb{Z}_2 .

Definition.-

Irreducible polynomial

a)False b)False a)True, b) True a)True, b) False a)False b)True

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1 solution

a) p ( x ) = x 2 + 1 = ( x + i ) ( x i ) p ( x ) p(x) = x^2 + 1 = (x + i)\cdot(x - i) \Rightarrow p(x) is not an irreducible polynomial over C \mathbb{C} . Furthemore, due to the fundamental theorem of algebra the only irreducible polynomials over C \mathbb{C} are of degree 1, so p ( x ) p(x) is not an irreducible polynomial over C \mathbb{C} .

b) p ( x ) = x 2 + 1 = ( x + 1 ) 2 = x 2 + 2 x + 1 p(x) = x^2 + 1 = (x + 1)^2 = x^2 + 2x + 1 in Z 2 [ x ] \mathbb{Z}_2[x] , then p ( x ) p(x) is not either an irreducible polynomial over Z 2 \mathbb{Z}_2 ,

Is there a classification of irreducible polynomials of Z p ( 2 ) \mathbb{Z}_p (2) ? E.g. are there degree n n polynomials that are irreducible?

Calvin Lin Staff - 4 years, 6 months ago

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I have had problems with mycomputer, like always. Let p be a prime number your question is relationed with the cyclotomical polynomials... For each p a prime number, I'm going to give you a proposition and later and example

Proposition.- Let F F be a field with caractheristic(p) 0 \neq 0 , for example, Z p \mathbb{Z}_p , then are equivalents:

a) F admits a cyclic extension of degree p.

b) There exists a F a \in F such that x p x a x^p - x - a is irreducible over F F

c) There exists a F a \in F such that β p β a , β F \beta^p - \beta \neq a, \forall \beta \in F .

Example.-

a) All extension F E F \subset E over finite fields is a cyclic extension.

b) The monic irreducible polynomials of degree 4 in Z 2 [ x ] \mathbb{Z}_2[x] are:

b1) x 4 + x 3 + x 2 + x + 1 x^4 + x^3 + x^2 + x + 1

b2) x 4 + x 3 + 1 x^4 + x^3 + 1

b3) x 4 + x + 1 x^4 + x + 1

Guillermo Templado - 4 years, 6 months ago

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Great! Thanks for shedding some light on these. There is so much deeper, richer theory in mathematics!

Calvin Lin Staff - 4 years, 6 months ago

Realize that there is not whole classification of groups under isomorphisms... There is only one whole classification of groups under isomorphims for finitely generated abelian groups... But I hope to be able to answer your question the best possible... For example, in R [ x ] \mathbb{R}[x] the irreducible polynomials has degree 1 or at most 2... in Q [ x ] \mathbb{Q}[x] the irreducible polynomials are able to have any degree ( think about the cyclotomic polynomials, Eisenstein's criterion...)

Guillermo Templado - 4 years, 6 months ago

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