The series is said to be Cesàro summable , with Cesaro Sum , if the average value of its partial sums tends to , meaning that
Is the series
Cesàro summable? If so, enter its Cesàro sum . If not, enter 666.
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I'm not making this a general policy, but I think I should write a solution to at least one problem with my name on it.
Let b n = n 1 ∑ k = 1 n s k . Then it's easy to check that b 2 m = 0 and b 2 m + 1 = 2 m + 1 m + 1 . The limit of this sequence does not exist, since the even terms go to 0 and the odd terms go to 1 / 2 .
Otto, I think you can change your redlink to this instead, at least for now.