Inspired by Patrick Corn

Calculus Level 4

1 2 + 3 4 + 5 6 + \large 1-2+3-4+5-6+\cdots

The series j = 1 a j \displaystyle \sum_{j=1}^{\infty} a_j is said to be Cesàro summable , with Cesaro Sum A A , if the average value of its partial sums s k = j = 1 k a j \displaystyle s_k=\sum_{j=1}^k a_j tends to A A , meaning that A = lim n 1 n k = 1 n s k A=\lim_{n\to\infty}\frac{1}{n}\sum_{k=1}^ns_k

Is the series 1 2 + 3 4 + 5 6 + 1-2+3-4+5-6 + \cdots

Cesàro summable? If so, enter its Cesàro sum A A . If not, enter 666.


Inspiration .


The answer is 666.

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1 solution

Patrick Corn
Feb 29, 2016

I'm not making this a general policy, but I think I should write a solution to at least one problem with my name on it.

Let b n = 1 n k = 1 n s k . b_n = \frac1{n} \sum_{k=1}^{n} s_k. Then it's easy to check that b 2 m = 0 b_{2m} = 0 and b 2 m + 1 = m + 1 2 m + 1 b_{2m+1} = \frac{m+1}{2m+1} . The limit of this sequence does not exist, since the even terms go to 0 0 and the odd terms go to 1 / 2 1/2 .

Otto, I think you can change your redlink to this instead, at least for now.

Yes, exactly! (+1) Thank you, Patrick!

I guess my strategy worked: Gently coerce somebody to write a solution (or two) by dedicating a problem (or two) to them ;)

It was "management" that put in the "red link"... so, I will let them change it if they wish.

Otto Bretscher - 5 years, 3 months ago

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