Note that 7 9 − 8 ≈ 0 . 8 8 8 and 3 2 0 − 1 7 ≈ 0 . 8 8 8 in the sense that the first 3 decimal places of these two numbers are equal.
Now we see that ⌊ 1 0 0 0 ( 7 9 − 8 ) ⌋ = ⌊ 1 0 0 0 ( 3 2 0 − 1 7 ) ⌋ = 8 8 8 .
Suppose ⌊ 1 0 0 0 ( x − y ) ⌋ = 8 8 8 where x , y are positive integers and x > 3 2 0 . What is the minimum value of x + y ?
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That is a nice pattern. I used a bit of brute force and looked for the next integer y such that ( y + 0 . 8 8 8 ) 2 and ( y + 0 . 8 8 9 ) 2 straddled an integer x , and was fortunate that I only had to go up to y = 2 6 .
In the problem, can you clarify what you mean by ≈ 0 . 8 8 8 ? This would help with understanding your intentions. My concerns are
What you have is a great pattern! If you want to approximate ( y + 9 8 ) 2 as an integer, then yes setting y = 9 n − 1 works out great and we're just off by 8 1 1 .
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This is a partial solution.
There is a nice pattern for integers x and y so that x − y ≈ 0 . 8 8 8 .
The pattern is as follows: x 1 = 7 9 , x n = ⌈ ( x n − 1 + 9 ) 2 ⌉ for all n ≥ 2 .
y n = 9 n − 1 .
After @Calvin Lin's comment: Here is a better way to understand: x n = ⌊ ( 9 n − 9 1 ) 2 ⌋ .
From the table below, the next value of x after 320 is 723, and the corresponding y is 26. So x + y = 7 2 3 + 2 6 = 7 4 9 .
(This solution is yet completed as we have not proved that 749 is the minimum value of x + y .)
Now you may want to prove that lim n → ∞ ( x n − y n ) = 9 8 = 0 . 8 8 8 8 8 8 8 8 8 8 8 8 . . .