Inspired by Sandeep Bhardwaj problem

Geometry Level 4

f ( x ) = sin ( x ) + sin ( 3 x ) + sin ( 5 x ) + + sin ( 40103 x ) cos ( x ) + cos ( 3 x ) + cos ( 5 x ) + + cos ( 40103 x ) \large f(x) = \dfrac{\sin(x) + \sin(3x) + \sin(5x) + \ldots + \sin(40103x)}{\cos(x) + \cos(3x) + \cos(5x) + \ldots + \cos(40103x)}

Fundamental period of f ( x ) f(x) can be represented as a π b \dfrac{a\pi}{b} , where a , b a, b are coprime numbers. Find a + b a + b .

Inspiration


The answer is 20053.

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1 solution

Aditya Sky
Mar 23, 2016

The given series simplifies to tan ( 20052 x ) \tan(20052\cdot x) . We know that tan ( x ) \tan(x) is a periodic function with fumdamental period π \pi , so, tan ( 20052 x ) \tan(20052\cdot x) is a periodic function with fundamental period 1 20052 π \frac{1}{20052} \cdot \pi . Hence, a + b = 1 + 20052 = 20053 a\,+\,b\,=\,1\,+\,20052\,=\,20053

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