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Γ ( n ) ≈ 2 π ( n − 1 ) ( e n − 1 ) n − 1 We want a very big n for good approximation. pi is small. for about 3 decimal places of accuracy 1000 is enough. so Γ ( 1 0 0 1 + π ) = Γ ( π ) i = 0 ∏ 1 0 0 0 ( π + i ) ≈ 2 π ( π + 1 0 0 0 ) ( e π + 1 0 0 0 ) π + 1 0 0 0 Γ ( π ) ≈ 2 π ( π + 1 0 0 0 ) ( e π + 1 0 0 0 ) π + 1 0 0 0 i = 0 ∏ 1 0 0 0 π + i 1 ≈ 2 . 2 8 8