I need to part ways

Logic Level 2

You are given 3 tiny empty unmarked beakers of distinct capacities. Denote $A,B,C$ as these beakers that can hold a maximum of 8 litres, 5 litres, and 3 litres respectively.

You are also given milk filled up to the brim of beaker $A$ .

What is the minimum number of moves required to divide the milk into two fours (i.e. separate them into 4 litres and 4 litres)?

Note that one move constitute of pouring milk from one beaker to another.

6 5 9 10 7 8

1 solution

Sravanth C.
Feb 9, 2015

Given below are the values for A, B and C.

A B C

8 0 0

3 5 0 (.............step 1 )

3 2 3 (.............step 2 )

6 2 0 (.............step 3 )

6 0 2 (.............step 4 )

1 5 2 (.............step 5 )

1 4 3 (.............step 6 )

4 4 0 (.............step 7 )

I actually found an alternate way of finding the same answer, after the fact.

a b c

8 0 0

5 0 3 (step 1)

5 3 0 (step 2)

2 3 3 (step 3)

5 0 1 (step 4)

5 1 0 (step 5)

4 1 3 (step 6)

4 4 0 (step 7)

Killian Macnish - 5 years, 8 months ago

WHAT HAPPENED IN STEP 4

Allen Rey Quicosa - 5 years, 8 months ago

thats nice! put it as solution

Sravanth C. - 5 years, 8 months ago

In step 1 Total milk = 5 + 0 + 3 = 8
.............2................ = 5 + 3 + 0 = 8
.............3.................= 2 + 3 + 3 = 8
.............4 ................= 5 + 0 + 1 = 6 ( 2 liter milk is missing)

azadali jivani - 5 years, 8 months ago

I need to part ways

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