Inspired Compound Figure

If τ ( n ) \tau(n) is the number of positive divisors of n n , find the smallest integer n n such that there exist different possible integer values of x x such that x < n ! x < n! and τ ( x ) = τ ( n ! ) \tau(x) = \tau(n!) , and give the sum of these different possible values of x x as your answer.

Inspiration: Immensely Compound Figure


The answer is 165480.

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1 solution

David Vreken
Oct 7, 2018

This is not a complete solution.

It was shown in the solutions to Immensely Compound Figure that 7 ! 7! has 60 60 divisors, but there are no smaller positive integers also with 60 60 divisors. A similar method can be used to show that this property is true for 1 n 7 1 \leq n \leq 7 .

However, for n = 8 n = 8 , 8 ! = 2 7 3 2 5 7 8! = 2^7 \cdot 3^2 \cdot 5 \cdot 7 and therefore has ( 7 + 1 ) ( 2 + 1 ) ( 1 + 1 ) ( 1 + 1 ) = 96 (7 + 1)(2 + 1)(1 + 1)(1 + 1) = 96 divisors. There are 5 5 positive integers smaller than 8 ! = 40320 8! = 40320 that also have 96 96 divisors: 36960 36960 , 27720 27720 , 37800 37800 , 30240 30240 , and 32760 32760 , and the sum of these numbers is 165480 \boxed{165480} .

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