A thin insulator rod is placed between two unlike point charges and .
Will the forces acting on the charges change?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Due to polarisation of the insulator rod, q 1 charge is acted upon, in addition to q 2 , by the polarisation charges induced at the ends A and B .
The attractive force exerted by the negative charge induced at end A will be stronger than the repulsive force exerted by the positive charge induced at the end B ( F ∝ r 2 1 ) .
Thus the total force acting on q 1 charge will increase.
Source: SS Krotov Problem 3 . 1