∫ 1 e x ln x d x = ?
Bonus: Find the value of the integral in two different ways.
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Simple standard approach.
Did the same. Easiest method for this ;)
Yup. Did in the same manner. !!!Substitution. By the way nice and clear sol.+1
Using integration by parts with u = ln x and v ′ = x − 1 :
∫ 1 e x ln x d x = [ ln 2 x ] 1 e − ∫ 1 e x ln x d x
⇒ 2 ∫ 1 e x ln x d x = 1
⇒ ∫ 1 e x ln x d x = 0 . 5
Parts is nice too. +1
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u = ln ( x ) ⇒ d x d u = 1 / x ⇒ x ⋅ d u = d x
∫ 1 e x ln ( x ) d x = ∫ 0 1 u ⋅ d u = [ 2 u 2 ] 0 1 = 0 . 5