Integer Coefficients

Algebra Level 4

At some integer points, a polynomial with integer coefficients can take the values of 1, 2, 3.

Then for how many integers can the polynomial take the value of 5?


The answer is 1.

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1 solution

Melissa Quail
Apr 2, 2018

We can use the fact that a b P ( a ) P ( b ) a - b | P(a) - P(b) for any polynomial P P and any integers a a and b b .

This fact is simple to prove using the factorisation x n y n = ( x y ) ( x n 1 + x n 2 y + . . . + x y n 2 + y n 1 ) x^n - y^n = (x - y)(x^{n-1} + x^{n-2}y + ... + xy^{n-2} + y^{n-1}) .

Then let a a be such that P ( a ) = 5 P(a) = 5 .

Then a a must satisfy:

( a 1 ) 4 (a - 1) | 4

( a 2 ) 3 (a - 2) | 3

( a 3 ) 2 (a - 3) | 2

(where a b a | b means b is divisible by a a )

The last condition means that a = 4 a = 4 or a = 5 a = 5 . However, a = 4 a = 4 doesn't satisfy the other two conditions so a = 5 a = 5 . This is clearly possible as a value since we can take the polynomial P ( x ) = x P(x) = x .

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