Integer ideals

Algebra Level 4

A nonempty set I I in a ring R R is called an ideal if

(1) it is closed under addition: a I , b I a + b I a\in I, b\in I \Rightarrow a+b \in I

(2) it "swallows up" under multiplication: a R , i I a i I a \in R, i \in I \Rightarrow ai \in I .

A proper ideal is one that is not equal to the entire ring.

A proper ideal is prime if a b I ab \in I implies that a I a\in I or b I b \in I .

A proper ideal is maximal if there are no ideals in between it and the entire ring: if J J is an ideal, then I J R I \subseteq J \subseteq R implies I = J I=J or J = R J=R .

How many ideals of Z \mathbb Z are prime but not maximal?


It should help to read the ring theory wiki!
1 Infinitely many 2 0

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1 solution

展豪 張
Mar 20, 2016

Only ( 0 ) (0) is prime but not maximal.

Agreed! Proof? :)

Patrick Corn - 5 years, 2 months ago

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First of all, Z \mathbb Z is a PIR .
Consider special cases ( 0 ) (0) and ( 1 ) (1) first. ( 0 ) (0) satisfies requirement while ( 1 ) (1) is maximal.
All other cases can be written as ( a ) (a) where a a is either prime or composite.
For prime a a , ( a ) (a) is maximal.
For composite a a , ( a ) (a) is not prime.
Hence only ( 0 ) (0) is prime but not maximal.
:)

展豪 張 - 5 years, 2 months ago

oops. ok (0) is a prime ideal. i missed this point.

Srikanth Tupurani - 2 years, 6 months ago

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