If is a integer
Find the summation for all possible number who satisfy as a integer.
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Here, k = n n + 1 2 = 1 + n 1 2
so k will be integer if 1 2 is divisible by n
Now the product of 1 2 is: 1 , 2 , 3 , 4 , 6 , 1 2
so, n = ± 1 , ± 2 , ± 3 , ± 4 , ± 6 , ± 1 2
Then the summation come 0 ..