Integer Sequence

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The terms of a sequence of positive integers satisfy a n + 3 = a n + 2 ( a n + 1 + a n ) a_{n+3} = a_{n+2}(a_{n+1}+a_{n}) , for n = 1 , 2 , 3 , … n = 1,2,3,\dots

If a 6 = 8820 a_6 = 8820 , what's the sum of the digits of a 7 a_7 ?


The answer is 27.

Alessio Di Lorenzo by Alessio Di Lorenzo , 25, Italy

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1 solution

Danyal Ahmad
Mar 9, 2014

The digits of 8820 add up to 18 showing that the next term,which is a product of it with another number,must have such digits which add up to a multiple of 9 ? I took a few chances and the answer came out to be 27.

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