INTEGER TYPE -1
Algebra
Level
pending
In a class of 10 students,there are 3 girls . The numbers of ways they can be arranged in a row , so that no two girls are consecutive, is K.8! where the sum of the digits of K is?
4
2
6
1
3
5
7
0
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1 solution
There are 8 gaps among 7 boys . The three girls can be arranged in these 8 places in 8 P 3 ways also the 7 boys can be arranged in 7! So; required number of permutations = 7! . 8 P 3 =42.8!
So: K=42 and sum of the digits of K Is 4+2= 6