Integral roots

Find the total number of integral values of a a such that the equation x 2 + a x + a + 1 = 0 x^2 + ax + a +1 = 0 has integral roots (of x x ).

Three Four Two They are infinitely many One

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1 solution

Kushal Bose
Aug 7, 2016

Let two integral roots are p , q p,q

Now p + q = a p+q=-a and p q = a + 1 p q=a+1

p + q + p q = a + a + 1 p+q+p q=-a+a+1

p + q + p q = 1 p+q+p q=1

1 + p + q + p q = 2 1+p+q+p q=2

( p + 1 ) ( q + 1 ) = 2 (p+1)(q+1)=2

As p p and q q are integers

Case(1): p + 1 = 2 p+1=2 and q + 1 = 1 q+1=1 or p + 1 = 1 p+1=1 and q + 1 = 2 q+1=2

From here a = 1 a=-1

Case(2) : p + 1 = 2 p+1=-2 and q + 1 = 1 q+1=-1 or p + 1 = 1 p+1=-1 and q + 1 = 2 q+1=-2

From here a = 5 a=5

So, a a has two values a = 1 , 5 a=-1,5

Awesome solution!😀 I never thought this way.

Anurag Pandey - 4 years, 10 months ago

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Thanks....

Kushal Bose - 4 years, 10 months ago

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