integrate :

Calculus Level 1

I = 2012 2012 sin 3 x + x 5 + 1 \int _{ -2012 }^{ 2012 }{ \sin ^{ 3 }{ x } +{ x }^{ 5 }+1 } dx

2012 0 4024 2013

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1 solution

Imran Sayed
Nov 6, 2014

I = 2012 2012 sin 3 x + x 5 + 1 d x I\quad =\quad \int _{ -2012 }^{ 2012 }{ \sin ^{ 3 }{ x } +{ x }^{ 5 }+1 } dx

I = 0 + 0 + 2012 2012 1 d x I\quad =\quad 0+0+\int _{ -2012 }^{ 2012 }{ 1 } dx

I = 2 0 2012 1 d x I\quad =\quad 2\int _{ 0 }^{ 2012 }{ 1 } dx

I = 2 × 2012 0 = 4024 I\quad =\quad 2\times 2012-0 = 4024

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