Integrate 2016
If the integral above is equal to , where and are positive integers, find .
The answer is 6051.
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1 solution
∫ 1 2 0 1 6 2 0 1 6 x 2 0 1 6 d x ∴ a + b + c = 2 0 1 6 × 2 0 1 6 + 1 x 2 0 1 6 + 1 ∣ 1 2 0 1 6 = 2 0 1 6 × 2 0 1 7 2 0 1 6 2 0 1 7 − 2 0 1 6 × 2 0 1 7 1 2 0 1 6 = 2 0 1 7 2 0 1 6 2 0 1 8 − 2 0 1 6 = 2 0 1 6 + 2 0 1 7 + 2 0 1 8 = 6 0 5 1