Integrate with sin cos #2

Calculus Level 5

0 π 4 ( sin 2 θ ) 5 2 ( sin θ + cos θ ) d θ = A B π \large{\displaystyle \int^{\frac{\pi}{4}}_{0} (\sin 2 \theta)^{\frac{5}{2}} (\sin \theta+\cos \theta) \, d\theta=\frac{A}{B} \pi}

If A A and B B are coprime integers, find A + B A+B .

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The answer is 37.

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1 solution

Tanishq Varshney
Sep 11, 2015

sorry i missed out d θ d \theta in one of the steps

I did it this way: Because sin ( 2 θ ) = 1 ( cos θ sin θ ) 2 \sin(2\theta) = 1- ( \cos\theta - \sin\theta)^2 , so I let y = cos θ sin θ y = \cos\theta - \sin\theta . Then for integration of cos 6 x \cos^6 x , I do reduction formula (Wallis Product): 5!!/6!! * pi/2 = 5pi/32.

Nice question by the way!

Pi Han Goh - 5 years, 9 months ago

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