∫ 0 4 π ( sin 2 θ ) 2 5 ( sin θ + cos θ ) d θ = B A π
If A and B are coprime integers, find A + B .
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I did it this way: Because sin ( 2 θ ) = 1 − ( cos θ − sin θ ) 2 , so I let y = cos θ − sin θ . Then for integration of cos 6 x , I do reduction formula (Wallis Product): 5!!/6!! * pi/2 = 5pi/32.
Nice question by the way!
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sorry i missed out d θ in one of the steps