Compute the following definite integral
If the answer can be expressed in , where are positive integers, then find the product .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Since an antiderivative for the integral is 1 7 ln ∣ x ∣ + 3 x , we can immediately apply the Newton-Leibnitz Formula to get: ∫ 1 5 ( x 1 7 + 3 ) d x = 1 7 ln + \dfrac{3x}{1}\right|_1^5 = 1 7 ln 5 + 1 5 − 3 = 1 7 ln 5 + 1 2
Therefore, 1 7 ∗ 5 ∗ 1 2 = 1 0 2 0