If
∫ 1 5 ∫ 1 x z → y lim z 3 + 1 z 5 + z 4 d x d y
is equivalent to ( A × tan − 1 ( B ) + C π + D × ln ( E ) + F ) ( H x − G ) , find the value of the digit sum of A 2 + B 2 + C 2 + D 2 + E 2 + F 2 + G 2 + H 2 , where A , B , C , D , E , F , G , H are integers.
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Yep. There is nothing much to do but just a little hard work.
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nothing much just integrate.all u have to do is
(y^5+y^4)/(y^3+1)
=y^4(y+1)/ (y+1)(y^2-y+1)
=y^4/ y^2-y+1
now divide,then partial fractions