Gauss' law is a very powerful method to determine the electric field due to a distribution of charges. The mathematical expression for Gauss' law is:
where is a surface, is the electric field vector, is the infinitesimal area element, is the charge enclosed by and is a constant.
We now turn to the notion of integration over a specified surface. One can think about definite integration over a line interval, i.e. , as the area under the curve defined by . Similarly, the integral over a surface of a function can be thought of as the volume under the 2-d graph of the function. Using this definition, what is the integral
where the surface is the square in the -plane with corners at .
This problem is part of David's set on Gauss' Law .
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We have like d A = d x d y , where x and y runs from 0 to 1 .
So, ∫ s x d A = ∫ ∫ x d x d y = ∫ 0 1 x d x ∫ 0 1 d y = 2 1