If I = ∫ ( 2 + x ) ( 5 − x ) . d x is of the form I = ( x + a ) ( b − x ) + c sin − 1 e x + d + k where k is constant of integration. Find a + b + c + d + e
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We can also make a substitution x = 5 cos 2 θ − 2 sin 2 θ
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Put x + 2 = t 2
d x = 2 t d t
The integration is reduced to
2 ∫ 7 − t 2 d t
Apply the formula. Plz upvote if u liked my solution