Intense Angle Chasing!

Geometry Level 4

Point H H is the orthocenter of triangle A B C ABC . Points D , E , D, E, and F F lie on the circumcircle of triangle A B C ABC such that A D B E C F AD || BE || CF . Points S , T , S, T, and U U are the respective reflections of D , E , D, E, and F F across the lines B C , C A , BC, CA, and A B AB . Given that two angles of quadrilateral S H U T SHUT (may not be in this orientation) are 39 39 degrees and 91 91 degrees. Find the positive difference between the other two angles.

51 49 52 50

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1 solution

Alan Yan
Sep 6, 2015

We will use complex numbers. Denote the complex number for each point by its lower case character and let the circumcenter be the origin and the circumcircle be the unit circle.

Let the real axis be the line through the circumcenter that is perpendicular to all three parallel lines. This implies that a = d , b = e , c = f a = \overline{d} , b = \overline{e} , c = \overline{f}

This implies that d = 1 a , e = 1 b , f = 1 c d = \frac{1}{a} , e = \frac{1}{b} , f = \frac{1}{c}

It is well-known that if a , b a, b are two complex numbers on the unit circle, then the reflection of complex number z z over line A B AB is a + b a b z a+b-ab\overline{z} .

This implies that

s = a + b a b c s = a+b - abc

t = a + c a b c t = a + c - abc

u = a + b a b c u = a + b - abc

It is well-known that if the circumcenter is the origin, then

h = a + b + c h = a + b + c .

Remark that these four points are concyclic by noticing their symmetry. It is easy to see that their center is a + b + c a b c a + b + c - abc . You can confirm this by subtracting the center with each point and taking the magnitude, which in this case, is one.

Therefore, since the two angles in cyclic quadrilateral S H U T SHUT are not supplementary, the other two angles must be supplementary to the given angles. Therefore the other two angles are 141 141 degrees and 89 89 degrees implying a positive difference of 52 \boxed{52}

This is an altered version of a problem from MOP \textit{This is an altered version of a problem from MOP }

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