What is interesting about the number 38?
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The key to proving the correct answer is noting that numbers ending in 5 (excluding 5 itself) are never prime.
The units digit of our even number must be 0 , 2 , 4 , 6 , or 8 .
If the units digit is 0 and our number is at least 3 0 , our number can be expressed as the sum of two composite numbers ending in 5 .
If the units digit is 2 , and our number is at least 4 2 , our number can be expressed as the sum of a composite number ending in 5 and the number 2 7 .
If the units digit is 4 and our number is at least 2 4 , our number can be expressed as the sum of a composite number ending in 5 and the number 9 .
If the units digit is 6 and our number is at least 3 6 , our number can be expressed as the sum of a composite number ending in 5 and the number 2 1 .
If the units digit is 8 and our number is at least 4 8 , our number can be expressed as the sum of a composite number ending in 5 and the number 3 3 .
The largest even number that could possibly fall outside of these cases is the number 3 8 . It isn't too much work to run through the pairs ( 1 , 3 7 ) , ( 3 , 3 5 ) , ( 5 , 3 3 ) , ( 7 , 3 1 ) , ( 9 , 2 9 ) , ( 1 1 , 2 7 ) , ( 1 3 , 2 5 ) , ( 1 5 , 2 3 ) , ( 1 7 , 2 1 ) , ( 1 9 , 1 9 ) and see that no pair of odd integers that adds to 3 8 contains two composite numbers.
Bonus:
Answer A is false; Goldbach's conjecture states that every even integer greater than 2 can be expressed as the sum of two primes. Goldbach's conjecture is unproven but has been verified for all even integers below 4 ∗ 1 0 1 8 . 3 8 , in particular, is 7 + 3 1 and 1 9 + 1 9 . Answer D is false for the same reason.
Answer C is false; 3 8 is the largest such integer, but smaller integers that cannot be the sum of two composite odds exist. For instance, 2 cannot be expressed in this manner. Also, literally all negative even integers, among several others.