interesting imaginary number operation

Algebra Level 3

i not an allowed expression 0.208 i+i i+i i*i+... .... ... 2.71i

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1 solution

Tom Engelsman
Sep 3, 2018

Let i = e i π 2 i = e^{i \cdot \frac{\pi}{2}} so that i i = ( e i π 2 ) i = e i 2 π 2 = e π 2 0.208 . i^i = (e^{i \cdot \frac{\pi}{2}})^i = e^{i^2 \cdot \frac{\pi}{2}} = e^{-\frac{\pi}{2}} \approx \boxed{0.208}.

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