n → ∞ lim n π n + e n = ?
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This is actually quite intuitive: π n grows faster than e n , since π > e . Therefore, we can essentially exclude e n from the limit: n π n = π .
Relevant wiki: L'Hopital's Rule - Basic
L = n → ∞ lim n π n + e n = n → ∞ lim exp ( ln ( n π n + e n ) ) = exp ( n → ∞ lim n ln ( π n + e n ) ) = exp ( n → ∞ lim 1 π n + e n π n ln π + e n ) = exp ( n → ∞ lim π n + e n π n ln π + e n ) = exp ( n → ∞ lim 1 + ( π e ) n ln π + ( π e ) n ) = exp ( ln π ) = π where exp ( x ) = e x A ∞ / ∞ case, L’H o ˆ pital’s rule applies. Differentiate up and down w.r.t. n . Divide up and down by π n .
Haha same.
I think if you use L 'Hopital's rule, you have to use the Heine theorem. Does n mean positive integers here?Is it real?
(By the way, My English level is limited)
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We can use just L'Hopital's rule here. I don't know what Heine theorem is . n is real and may not necessary be an integer.
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Relevant wiki: Squeeze Theorem
Note that π = n π n ≤ n π n + e n ≤ n π n + π n = π n 2
And n → ∞ lim π n 2 = π
By the squeeze theorem, we get n → ∞ lim n π n + e n = π