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1 solution
a^2 + b^2 + 2c^2 - 4a + 2c - 2bc + 5 = (a - 2)^2 + (b - c)^2 + (c + 1)^2 = 0. therefore a = 2, b = c, c = -1 = b, so a + b - c = a = 2. Ed Gray