At a temperature of , a 0.04 in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [ ] bar with a width of 3 in and a thickness of 0.75 in. Bar (2) [ ] bar with a width of 2 in and a thickness of 0.75 in.
Assume the supports at and are rigid. What is the lowest temperature at which the two bars contact each other?
Equations to be used:
a) Elongation or lengthening .
b) .
Note : Since there is a gap of 0.04 in between the two bars, the sum of the elongations of bar (1) and (2) is given as shown in equation (b).
Symbols:
: Thermal expansion of a bar
: Length
: Temperature
: Elongation.
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𝛿= αΔTL and 𝛿1+𝛿2= 0.04
α1ΔTL1 + α2ΔTL2 = 0.04
( 12.5 x 10^-6 ) ( ΔT) (32) + ( 9.6 x 10^-6 ) (ΔT) (44) = 0.04
solve for ΔT = 48.6
Tf= ΔT + Ti
Tf= 48.6 + 60 = 108.6 °F ( answer)