Cryptogram of an Interesting Product - 1

Logic Level 3

A B C D E F G I × I A A A A A A A A A \large{\begin{array}{cccccccc} &A&B&C& D& E & F& G &I\\ \times &&&& & & & & I\\ \hline &A& A&A&A& A& A & A& A &A\\ \hline \end{array}}

Find A+B+C+D+E+F+G+I

Assumption

Different alphabets are different positive single digit integers

33 39 35 37

Harish Sasikumar by Harish Sasikumar , 32, India

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1 solution

Harish Sasikumar
Nov 28, 2015

12345679 × 9 = 111111111 12345679 \times 9 = 111111111

A = 1 , B = 2 , C = 3 , D = 4 , E = 5 , F = 6 , G = 7 , I = 9 A=1, B=2,C=3,D=4,E=5,F=6,G=7,I=9 Note: there are no 8's A + B + C + D + E + F + G + I = 37 A+B+C+D+E+F+G+I=37

Extra: Can you make similar problem with the product 222222222 ?

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Sorry sir but shouldn't there be another A at the bottom? Interesting problem though!

Noel Lo - 5 years, 6 months ago

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Yes. You are correct. I've edited the problem accordingly.

Harish Sasikumar - 5 years, 6 months ago

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