Fractions Please!

Algebra Level 1

Find the natural number x x satisfying

x 1 x = 38 38 39 . x - \dfrac1x = 38\dfrac{38}{39}.

29 24 39 44

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Rajdeep Ghosh
Aug 24, 2016

Since x 1 x = 38 ( 38 39 ) x-\frac{1}{x}=38(\frac{38}{39}) x 1 x = 38 + ( 38 39 ) x-\frac{1}{x}=38+(\frac{38}{39}) x 1 x = 38 + ( 39 1 39 ) x-\frac{1}{x}=38+(\frac{39-1}{39}) x 1 x = 38 + 1 ( 1 39 ) x-\frac{1}{x}=38+1-(\frac{1}{39}) x 1 x = 39 ( 1 39 ) x-\frac{1}{x}=39-(\frac{1}{39}) so, x = 39 x-=39 I've checked it with a calculator. If you try to do it by Sreedharacharya's rule then you'll end up with something like ( 39 + 1524 ) / 2 (-39+-\sqrt{1524})/2

If you write 38 38 39 38 \frac{38}{39} , it looks like you're multiplying 38 by the fraction; you may want to explicit that you're doing an addition.

Roberto Gallotta - 4 years, 9 months ago

Log in to reply

It's the commonest of the basics in mathematics that a mixed friction is an integer + a fraction.

Rajdeep Ghosh - 4 years, 9 months ago
Loo Soo Yong
Sep 15, 2016

Since this is a multiple choice question - you can just plug the possible answers and check whether the solution checks out.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...