Intern at the Laborious Laboratory

Logic Level 3

Your job as an intern is to measure out precisely 1 60 \frac{1}{60} liters of hydrochloric acid. Unfortunately, you don't have flasks or beakers that can directly measure that quantity. In fact, all you can use for this task is:

(1) 3 Erlenmeyer flasks, each marked as being able to hold 1 3 , 1 4 \frac{1}{3},\frac{1}{4} , and 1 5 \frac{1}{5} liters, respectively.
(2) A tank of some unknown quantity of hydrochloric acid for filling your flasks, and
(3) A chemical disposal zone for dumping hydrochloric acid (dumping back into the tank is not allowed).

What is the minimum amount of hydrochloric acid that, when poured out of the tank (through some unknown means), allows us to knowingly and successfully measure 1 60 \frac{1}{60} liters of hydrochloric acid with the equipment provided?

3 5 \frac35 7 20 \frac7{20} 2 5 \frac25 2 3 \frac23 1 60 \frac1{60}

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2 solutions

First of all, let's convert the fractions 1 3 \frac{1}{3} , 1 4 \frac{1}{4} , and 1 5 \frac{1}{5} to 20 60 \frac{20}{60} , 15 60 \frac{15}{60} , and 12 60 \frac{12}{60} . Since the desired amount of hydrochloric acid is 1 60 \frac{1}{60} , we can scale the unit of measure down buy a factor of 60 (1/60 liter = 1 unit) which enables us to work with only integers.

When modeling the procedure, I use the format (12 unit flask, 15 unit flask, 20 unit flask) to denote the amount of HCl in each flask at any given step in the procedure.

So we have flasks of 20 20 , 15 15 ,and 12 12 units, and we want to measure 1 1 unit. Since we are careful, we start by filling the 15 unit flask. However, filling the 15 unit flask only allows for us to measure shifted variations of ( 0 , 15 , 0 ) (0,15,0) and ( 12 , 3 , 0 ) (12,3,0) , so clearly 15 units -- and anything less -- doesn't give the intern enough flexibility to measure out 1 unit of HCl.

However, if we use our 15 units to achieve the setup ( 0 , 12 , 3 ) (0,12,3) , we can add 3 units to fill up the 15 unit flask, and we get ( 0 , 15 , 3 ) (0,15,3) . 18 total units of HCl allows for much more transfer options than 15 units, yet even so, none of the possibilities using only 18 units involve a flask having a non-multiple of 3 amount of HCl. So 18 units isn't enough, and in fact anything less than 20 units only allows the intern to measure 3*x units of HCl.

So let's try 20 units of HCl. Note that ( 0 , 0 , 20 ) (0,0,20) must be the initial setup if your last move was to increase the amount of HCl to 20 units. With that in mind, let's see what happens:

( 0 , 0 , 20 ) (0,0,20) ( 0 , 15 , 5 ) (0,15,5) ( 12 , 3 , 5 ) (12,3,5) ( 0 , 3 , 17 ) (0,3,17) ( 3 , 0 , 17 ) (3,0,17) ( 3 , 15 , 2 ) (3,15,2) ( 12 , 6 , 2 ) (12,6,2) ( 0 , 6 , 14 ) (0,6,14)

At this point, it is impossible to make another transfer without quickly leading to one of the previous steps, so 20 units is still not enough. However, we can do the following:

( 0 , 6 , 14 ) (0,6,14) ( 6 , 0 , 14 ) (6,0,14) ( 6 , 14 , 0 ) (6,14,0) ( 6 , 15 , 0 ) (6,15,0)

In that last step, we added 1 unit to fill up the 15 unit flask. Look at what happens next!

( 6 , 15 , 0 ) (6,15,0) ( 6 , 0 , 15 ) (6,0,15) ( 1 , 0 , 20 ) (1,0,20)

So 21 units, as it turns out, is all we need to measure 1 unit of HCl! Since anything less does not work, 21 units is the minimum . 21 units = 21/60 liters = 7 20 \boxed{\frac{7}{20}}

Why can't you just go to one of the other near by labs in the building and borrow a flask that can measure 1/60?

Daniel Paddock - 5 years, 4 months ago

Just take the beaker of (20/60)l and use use that beaker to attempt fill (12/60)l beaker. After the (12/60)l beaker is full, there will be (8/60)l still left in the first (20/60)l beaker. Empty this to the (15/60)l beaker. Now there is (8/60)l in the (15/60)l beaker. Repeat this process again so that the (15/60)l beaker is full. Now the amount that is remaining that cannot be poured into the (15/60)l beaker is exactly (1/60)l. Considering the waste,the amount used is 21/60 l.

Sid Varma - 5 years, 2 months ago

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I used a similar approach - but isn't the total volume of dispensed HCl 28/60 because you had to refill the 20/60 the first time with fresh HCl plus reuse the 12/60 left in the small beaker from the second time with 8/60 fresh HCl?

Faraz Arastu - 4 years, 11 months ago
Valentino Henry
Aug 15, 2015

You have done a great job Of copying

harsha varma - 3 years, 8 months ago

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