Internal energy

Classical Mechanics Level 5

Define $A\to B$ as the change in internal energy from A to B.

Find the value of $\{A\to E \}+ \{ A\to B\} - 2\{A\to C\} - 2\{C\to D\} -2\{D\to E\} - \{E\to F\} -\{F\to B\}$

2.156 1.238 1.236 None of these

1 solution

Trevor Arashiro
Mar 31, 2016

$\Delta \text{IE}=\displaystyle \int P~\Bbb{d}V$

$\Delta \text{IE}\vert _X^Y=X \to Y=\displaystyle \int_X^Y P~\Bbb{d}V$

$\color{#3D99F6}{ \{A\to E \}-2\{C\to D\}}+\color{#D61F06}{ \{ A\to B\} - 2\{D\to E\} -\{F\to B\}} +2\{A\to C\}- \{E\to F\}$

$\color{#3D99F6}{0}+\color{#D61F06}{0}+2\cdot0-0$

$\boxed 0$

Not sure if this is completely wrong. May have gottenIE mixed up with something else. Can someone confirm this?

Trevor Arashiro - 5 years, 2 months ago

We can do this geometrically also. We will see that all the forward(+ve) and backward(-ve) steps cancel out. Thus giving a 0. :P

rajdeep das - 4 years, 8 months ago