Internal Tension Due to Gravity

A $10^{15} \, \text{kg}$ point-mass is located $1 \, \text{m}$ away from the close end of a $1 \, \text{kg}$ rigid rod. The rod is $1 \, \text{m}$ long, and its mass is uniformly distributed over its length.

The entire rod accelerates at the same rate toward the point-mass. In order for this to happen, there must be an internal mechanical retarding force exerted by the farther half of the rod on the closer half.

What is the magnitude (absolute value) of this force, in Newtons?

Details and Assumptions:
- Universal gravitational constant $G = 6.67 \times 10^{-11} [\text{SI units}]$
- Neglect the effects of General Relativity